Cоnsider the fоllоwing potentiаl proof for the stаtement ``the sum of two even integers is even." Proof: Suppose x аnd y are even. Let x = 2 k and y = 2 k where k is an integer. x + y = 2 k + 2 k = 4 k = 2 ( 2 k ) = 2 m , where m = 2 k . Since k is an integer, m = 2 k is an integer. So, x + y = 2 m , where m is an integer. Therefore, x + y is even. {"version":"1.1","math":"text{Consider the following potential proof for the statement}\ text{``the sum of two even integers is even."}\ text{Proof:}\ text{Suppose $x$ and $y$ are even.}\ text{Let $x=2k$ and $y=2k$ where $k$ is an integer.}\ begin{array}{rcl} x+y&=&2k+2k\ &=&4k\ &=&2(2k)\ &=&2m, text{where }m=2k. end{array}\ text{Since $k$ is an integer, $m=2k$ is an integer.}\ text{So, $x+y=2m$, where $m$ is an integer.}\ text{Therefore, $x+y$ is even.}"} Select all true statements.