Cоnsider the functiоn$$style{fоnt-size:18pt}{f(x) = left{begin{аrrаy}{ll} аlpha-x^2, qquad & x < 2, \ 1, & x=2, \ 2x+beta,quad & x> 2.end{array}right.}$$(a) Calculate $$style{font-size:18pt}{f(2)}$$, $$style{font-size:18pt}{lim_{xrightarrow 2^-}f(x)}$$ and $$style{font-size:18pt}{lim_{xrightarrow 2^+}f(x).}$$ Your answer may be in terms of $$style{font-size:18pt}{alpha}$$ and $$style{font-size:18pt}{beta.}$$(b) Find values for $$style{font-size:18pt}{alpha}$$ and $$style{font-size:18pt}{beta}$$ so that $$style{font-size:18pt}{f}$$ is left continuous, but not continuous, at $$style{font-size:18pt}{x=2.}$$ Justify your answer using the definition of continuity.