The following completed proof is correct. (x)(Mx ⊃ Nx) (x)(…

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The fоllоwing cоmpleted proof is correct. (x)(Mx ⊃ Nx) (x)(Nx ⊃ Ox) / (x)(Mx ⊃ Ox) Mа ACP Mа ⊃ Nа 1, UI Na ⊃ Oa 2, UI Ma ⊃ Oa 4, 5, HS Oa 3, 6, MP Ma ⊃ Oa CP, 3–7 (x)(Mx ⊃ Ox) 8, UG

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