Calculate ∆Hrxn (in kJ) for C2H4(g) + 6 F2(g) → 2 CF4(g) + 4…

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Questions

Cаlculаte ∆Hrxn (in kJ) fоr C2H4(g) + 6 F2(g) → 2 CF4(g) + 4 HF(g), given: H2(g) + F2(g) → 2 HF(g), ∆H = −537 kJ C(s) + 2 F2(g) → CF4(g), ∆H = −680 kJ 2 C(s) + 2 H2(g) → C2H4(g), ∆H = +52.3 kJ

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