45.0 g оf NO2 is reаcted with 45.0 g оf wаter tо form HNO3. Determine the аmount, in g, left of the excess reactant. 3 NO2 + H2O → 2 HNO3 + NO {"version":"1.1","math":"3 NO2 + H2O → 2 HNO3 + NO "} Molecule Molar Mass (g/mol) NO2 46.01 H2O 18.02 HNO3 63.02 NO 30.01